IP Addressing & Subnetting

One or more correct

• A202.16.0.0/19
• B202.17.64.0/19
• C202.16.32.0/19
• D202.17.24.0/19

Numerical answer

Subnet Address    Subnet Mask (in CIDR notation)    Interface
145.36.0.0        /16                              E1
145.36.128.0      /17                              E2
145.36.64.0       /18                              E3
145.36.255.0      /24                              E4
Default           --                               E5

Single correct

• AE3
• BE1
• CE2
• DE5

Numerical answer

Single correct

• AInternet Control Message Protocol (ICMP)
• BInternet Group Management Protocol (IGMP)
• COpen Shortest Path First (OSPF)
• DRouting Information Protocol (RIP)

Single correct

• A5 fragments, 1488 bytes
• B6 fragments, 88 bytes
• C6 fragments, 108 bytes
• D6 fragments, 116 bytes

One or more correct

• ASource IP
• BDestination IP
• CHeader Checksum
• DTotal Length

Prefix            Next hop router
10.1.1.0/24       R1
10.1.1.128/25     R2
10.1.1.64/26      R3
10.1.1.192/26     R4

Numerical answer

Numerical answer

One or more correct

• AThe destination IP address is the IP address of R
• BThe destination IP address is the IP address of Y
• CThe destination MAC address is the MAC address of S
• DThe destination MAC address is the MAC address of Y

One or more correct

• AThe fragmentation of an IP datagram is performed only at the source of the datagram
• BThe fragmentation of an IP datagram is performed at any IP router which finds that the size of the datagram to be transmitted exceeds the MTU
• CThe reassembly of fragments is performed only at the destination of the datagram
• DThe reassembly of fragments is performed at all intermediate routers along the path from the source to the destination

One or more correct

• ASource IP Address
• BProtocol
• CTime to Live (TTL)
• DHeader Checksum

Single correct

• A10.12.2.0/23
• B10.12.2.0/24
• C10.12.0.0/22
• D10.12.2.0/22

Subnet Number    Subnet Mask        Interface ID
200.150.0.0      255.255.0.0        1
200.150.64.0     255.255.224.0      2
200.150.68.0     255.255.255.0      3
200.150.68.64    255.255.255.224    4
Default                             0

Numerical answer

Answer key coming soon

Single correct

• A3
• B12
• C6
• D8

Answer key coming soon

Subnet Number    Subnet Mask        Next Hop
12.20.164.0      255.255.252.0      R1
12.20.170.0      255.255.254.0      R2
12.20.168.0      255.255.254.0      Interface 0
12.20.166.0      255.255.254.0      Interface 1
default                             R3

One or more correct

• A12.20.164.0/20
• B12.20.164.0/22
• C12.20.164.0/21
• D12.20.168.0/22

Answer key coming soon

One or more correct

• ATwo fragments are created at $R$ and the IP datagram size carrying the second fragment is 620 bytes.
• BIf the second fragment is lost, $R$ will resend the fragment with the IP identification value 0x1234.
• CIf the second fragment is lost, $P$ is required to resend the whole TCP segment.
• DTCP destination port can be determined by analysing *only* the second fragment.

Answer key coming soon

Single correct

• AI and II only
• BI only
• CII and III only
• DII only

Answer key coming soon

Single correct

• AI and II only
• BII and III only
• CIII and IV only
• DI and IV only

Answer key coming soon

Single correct

• AM, N, and P all belong to the same subnet
• BOnly M and N belong to the same subnet
• COnly N and P belong to the same subnet
• DM, N, and P belong to three different subnets