C Programming

#include <stdio.h>
int main(){
   int a = 6;
   int b = 0;
   while(a < 10) {
      a = a / 12 + 1;
      a += b;}
   printf("%d", a);
   return 0;}

Single correct

• AThe program prints 9 as output
• BThe program prints 10 as output
• CThe program gets stuck in an infinite loop
• DThe program prints 6 as output

#include <stdio.h>
void fX();
int main(){
   fX();
   return 0;}
void fX(){
   char a;
   if((a=getchar()) != '\n')
       fX();
   if(a != '\n')
       putchar(a);}

Single correct

• AThe program will not terminate
• BThe program will terminate with no output
• CThe program will terminate with 4321 as output
• DThe program will terminate with 1234 as output

int f(int x, int y) {
  for (int i=0; i<y; i++) {
    x=x+x+y;
  }
  return x;
}

One or more correct

• AIf the inputs are x=20, y=10, then the return value is greater than $2^{20}$
• BIf the inputs are x=20, y=20, then the return value is greater than $2^{20}$
• CIf the inputs are x=20, y=10, then the return value is less than $2^{10}$
• DIf the inputs are x=10, y=20, then the return value is greater than $2^{20}$

#include <stdio.h>
int g(int p) { printf("%d", p); return p; }
int h(int q) { printf("%d", q); return q; }
void f(int x, int y) {
  g(x);
  h(y);
}
int main() {
  f(g(10),h(20));
}

Single correct

• A20101020
• B10202010
• C20102010
• D10201020

int fX(char *a){
    char *b = a;
    while(*b)
        b++;
    return b - a;}

One or more correct

• AThe function call fX("abcd") will always return a value
• BAssuming a character array c is declared as char c[] = "abcd" in main(), the function call fX(c) will always return a value
• CThe code of the function will not compile
• DAssuming a character pointer c is declared as char *c = "abcd" in main(), the function call fX(c) will always return a value

#include <stdio.h>
int main() {
    double a[2]={20.0, 25.0}, *p, *q;
    p = a;
    q = p + 1;
    printf("%d,%d", (int)(q - p), (int)(*q - *p));
    return 0;}

Single correct

• A4,8
• B1,5
• C8,5
• D1,8