Intermediate Code

t0 = i * 1024
t1 = j * 32
t2 = k * 4
t3 = t1 + t0
t4 = t3 + t2
t5 = X[t4]

Single correct

• AX is declared as "int X[32][32][8]".
• BX is declared as "int X[4][1024][32]".
• CX is declared as "char X[4][32][8]".
• DX is declared as "char X[32][16][2]".

Single correct

• Amake parsing and semantic analysis simpler.
• Bimprove error recovery and error reporting.
• Cincrease the chances of reusing the machine-independent code optimizer in other compilers.
• Dimprove the register allocation.